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Venice is a city in Sarasota County, Florida, United States. As of the 2010 census, the city had a population of 20,748. It is noted for its large snowbird population. Venice is a principal city of the Bradenton-Sarasota-Venice, Florida Metropolitan Statistical Area.
According to the United States Census Bureau, the city has a total area of 16.6 square miles (43.1 km2). 15.3 square miles (39.5 km2) of it is land, and 1.4 square miles (3.5 km2), or 8.19%, is water.
As of the census of 2000, there were 17,764 people, 9,680 households, and 5,362 families residing in the city. The population density was 1,948.8 inhabitants per square mile (752.1/km²). There were 13,516 housing units at an average density of 1,482.8 per square mile (572.2/km²).
There were 9,680 households out of which 7.0% had children under the age of 18 living with them, 49.2% were married couples living together, 4.8% had a female householder with no husband present, and 44.6% were non-families. 40.3% of all households were made up of individuals and 30.3% had someone living alone who was 65 years of age or older. The average household size was 1.76 and the average family size was 2.25.
In the city the population was spread out with 6.9% under the age of 18, 2.3% from 18 to 24, 10.2% from 25 to 44, 23.1% from 45 to 64, and 57.5% who were 65 years of age or older. The median age was 69 years. For every 100 females there were 76.8 males. For every 100 females age 18 and over, there were 75.8 males.
The median income for a household in the city was $37,536, and the median income for a family was $46,898. Males had a median income of $35,271 versus $26,132 for females. The per capita income for the city was $28,220. About 3.7% of families and 5.7% of the population were below the poverty line, including 14.4% of those under age 18 and 3.7% of those age 65 or over.